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/Meta855 871 0 R 1 i >> q q endobj q /Type /XObject /Length 70 /Subtype /Form (6\)) Tj 1 i 1610 0 obj ET /BBox [0 0 88.214 16.44] stream /Resources<< >> q q 1.005 0 0 1.007 102.382 146.798 cm 0 G /F3 12.131 Tf /F3 17 0 R ET 1.014 0 0 1.007 111.416 453.193 cm stream << BT 1 i 1.005 0 0 1.007 102.382 683.553 cm /ProcSet[/PDF/Text] q 1.005 0 0 1.007 102.382 614.294 cm >> /BBox [0 0 549.552 16.44] Q /Meta920 936 0 R Q 0.737 1.417 l /ProcSet[/PDF] /F3 17 0 R >> BT endobj 41.187 20.154 l >> q >> ET /Resources<< /F3 12.131 Tf /BBox [0 0 88.214 16.44] q 106 0 obj 1.007 0 0 1.007 551.058 289.832 cm /Matrix [1 0 0 1 0 0] q /FormType 1 /Meta1130 Do ET >> endstream endstream ET q /Resources<< 1 i /Meta169 Do 0 5.336 TD q /Type /XObject >> 1 i q /F3 17 0 R 0 g Q Q endstream 0 g /Type /XObject Two life insurance companies determine their premiums using different formulas: Company A: p = 2a + 24 Company B: p = 2.25a + 13, where p represents the annual premium, and a represents the client's age. 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